Mini4x: Don't use improper fastners.. especailly on things like suspensions and/or brakes. Sometime a higher 'grade' is not nessicarily better.
Grade 5 bolts is some situations are "safer" and the equivalent grade 8, as they'll give (stretch) instead of snapping.
I'd just get them from Suzuki, it can't be that hard.
Sorry, gotta call
on this urban legend!
A Grade 5 bolt will fail before a Grade 8 bolt stretches. There is
nothing a Grade 5 bolt will do better than a Grade 8 - except cost you less to buy.
Let’s look at an example of where grade 5 and grade 8 bolts are subjected to single shear loads.
(The type which a shock mount bolt would be subjected to.)
Using a .250-inch diameter grade 8 fastener gives you the following shear capability:
A = Cross-sectional area of the fastener size (since bolt bodies/shanks have circular cross-sections, use area of a circle) = Pi x r2 where R (radius) = .250/2 = .125, therefore A = Pi x (.125)2 = .0491 square inches (in2)
Capability in shear = 91,000 lbs / in2 x .0491 in2 =
4468 lbsUsing the same .250-inch diameter grade 5 fastener results in the following:
Capability in shear = 75,000 lbs / in2 x .0491 in2 =
3683 lbsCalculating the tensile (clamping) capability is not as easy as shear since the thinnest portion of the bolt is at the minor diameter of the threads (bottom of the thread “V”). So you need to know the nominal minor diameter of that particular fastener. That’s where military specification MIL-S-8879C comes in. It is titled “Screw threads, controlled radius root with increased minor diameter, general specification for”. It lists that and a lot more for almost all possible fasteners. MIL-S-8879C lists the nominal minor diameter of a .2500-28-UNF at .2065 inches. Calculate the A (area) of the cross-section:
A = Pi x r2 = Pi x (.2065/2)2 = .03349 in2
Grade 5 bolt capability in yield (stretch) = 92,000 lbs / in2 x .03349 in2 = 3081 lbs minimum
Grade 5 bolt capability in tension (failure) = 120,000 lbs / in2 x .03349 in2 =
4019 lbs minimum
Grade 8 bolt capability in yield (stretch) = 130,000 lbs / in2 x .03349 in2 =
4354 lbs minimum
Grade 8 bolt capability in tension (failure) = 150,000 lbs / in2 x .03349 in2 = 5024 lbs minimum
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